Question

Ravi has a total of 30 coins of 50 paise, 50
coins each of 25 paise and 10 paise in a jar.
He spent 10 to buy chocolates. How much
money is left in the jar?​

Answer 1

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Answer 2

The sum of money left in the jar is Rs. 22.5.

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Let's solve the given problem:

We know,

$\boxed{\bold{1 \:rupees = 100 \:paise}}$ or $\boxed{\bold{1\:paise = \frac{1}{100}\:rupees }}$

So,

50 paise = $\frac{50}{100} = Rs. \:0.50$

25 paise = $\frac{25}{100} = Rs. \:0.25$

10 paise = $\frac{10}{100} = Rs. \:0.10$

The number of 50 paise coins Ravi has = 30

The number of 25 paise coins Ravi has = 50

The number of 10 paise coins Ravi has = 50

Therefore,

The total sum of money Ravi has in the jar is,

= $[30 \times Rs. 0.50] + [50 \times Rs. 0.25] + [50 \times Rs.\:0.10]$

= $Rs. \:15 + Rs. \:12.5+ Rs.\:5$

= $Rs. \:32.50$

The sum of money spent on buying chocolates = Rs. 10

Now,

The sum of money left with him in the jar is,

= [Total money] - [Money spent on chocolates]

= $Rs.\:32.50 - Rs.\:10$

= $\bold{Rs. \:22.50}$

Thus, the sum of money left with Ravi in his jar is Rs. 22.50.

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