Math, asked by nishathomas045, 7 months ago

Ravi is 6 years older than Neeta. Three years ago, he was twice as old as she was then. Find their present ages.​

Answers

Answered by honeyhansy321
4

Step-by-step explanation:

let,

Neeta age be x yrs

then, Ravi age = x+6 yrs

Three years ago..,

Neeta age will be x-3 yrs

Ravi age will be x+6-(3) yrs

In problem...

Ravi age is twice as Neeta age 3 years ago...

So, Ravi age is equal to 2(x-3) yrs..

According to the problem:

Ravi age 3yrs ago..

x+6-(3) = 2(x-3)

x+6-3 = 2x - 6

x + 3 = 2x - 6

x - 2x = - 6 - 3

-x = -9

So , x = 9

So finally,

Neeta's present age is (x) = 9yrs and Ravi's present age is (x+6) = 15yrs

I HOPE THIS ANSWER HELPS YOU....

Answered by Anonymous
7

Given :-

  • Ravi is 6 years older than Neeta. Three years ago, he was twice as old as she was.

To Find :-

  • Their present Age = ?

Solution :-

Let the present age of ravi be x years.

  • It is given that, Ravi is 6 years older than Neeta.

Therefore, Age of Neeta will be x - 6 years.

  • It is also given that,Three years ago, he was twice as old as Neeta.

Three years ago :

  • Age of Ravi = x - 3 years
  • Age of Neeta = x - 6 - 3 = x - 9 years

According to Question :-

→ x - 3 = 2(x - 9)

→ x - 3 = 2x - 18

→ -3 + 18 = 2x - x

→ 15 = x

x = 15 Years

Hence,

  • Present Age of Ravi = x = 15 years.
  • Present Age of Neeta = x - 6 = 15 - 6 = 9 years.
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