Math, asked by editzmaitu, 1 month ago

ravi is five year older than his sister roopali. their father is 20 years older than ravi.four year ago, the father's age was twice the sum of ages of ravi and roopali . find the present age of each​

Answers

Answered by Maddy000
2

Answer:

present ages

let the age of Ravi be x...(1)

so roopalis age is x-5..(2)

father's age is x+20..(3)

four year ago, the father's age was twice the sum of ages of ravi and roopali

let's find each one's age 4 yrs ago

father's age is x+20-4 = x+16

ravis age is x-4

roopalis is x-5-4 = x-9

sum of ages of Ravi and roopa is

x-4+x-9 = 2x-13

four year ago, the father's age was twice the sum of ages of ravi and roopali

ie x+16 = 2(2x-13)

we get x = 14

so from (1) (2) (3)

ravis age is 14

roopa age is 14-5 =9

fathers age is 14 +20 = 34

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