Question

Ravi is now 6 years older than Neeta. Three years ago he was twice as old as she was then. Find their present ages​

Answer 1

Answer:-

Ravi age →15 years.

Neeta age → 9 years

Given :-

Ravi is 6 years older than Neeta.

Three years ago he was twice as old as she was then.

To find :-

Their present ages.

Solution:-

Let the present age of Ravi be x years and Neeta be y years.

A/Q

→$x = y + 6-----eq.1$

Now, 3 years ago their ages was,

3 years ago ravi age = ( x - 3)

3 years ago Neeta age = ( y - 3)

→$x - 3 = 2 (y -3)$

→$x -3 = 2y -6$

→$x -2y = -6 + 3$

→$x - 2y = -3------eq. 2$

put the value of x in eq. 2

→$y + 6 -2y = -3$

→$-y = -9$

→$y = 9 years$

x = y + 6

x = 9 + 6

x = 15 years

hence,

Ravi age will be 15 years and Neeta age will be 9 years.

Answer 2

Answer:

Present age of Ravi = 15 Years

Present age of Neeta = 9 Years

Step-by-step explanation:

let the age of Ravi be x

since

Ravi is 6 years older than Neeta

so,

age of neeta = x - 6

given ,

three years ago

age of Ravi will twice as old as Neeta

so,

three years ago ,

age of Ravi = x - 3

Age of Neeta = x - 6 - 3

= x - 9

so,

ATQ,

x - 3 = 2(x - 9)

x - 3 = 2x - 18

2x - x = -3 + 18

x = 15

so,

age of Ravi = 15 years

and

age of Neeta = x - 6

= 15 - 6

= 9 years

so,

Present age of Ravi = 15 Years

Present age of Neeta = 9 Years