Question

Ravi is twice as old as his son. 16 years ago he was six times as old as his son. Find their present ages.

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Answer 1

Answer:

Fathers age = 42 years

Sons age      = 18 years

Step-by-step explanation:

Let the present ages of father and son be x and y, respectively.

As per the problem, six years ago,

(x−6)=3(y−6)

Six years later, (x+6)=2(y+6)

Solving these two equations, we get father's age is 42 years, and son's age is 18 years.