Math, asked by akankshya185, 6 months ago

Ravi is twice as old as his son.Sisteen years ago,he was six times as old as his son.Find their present ages.​

Answers

Answered by pds39937
2

Step-by-step explanation:

X = age of father 12 years ago Y = Age of son 12 years ago (X+12) = 2(Y+12) X+12 =2Y + 24 X = 2Y +24 - 12 X= 2Y + 12 ——-(1) X=6Y (12 years ago their ...

Answered by bhumikapatil767
0

Answer:

let the present age of ravi be=x

let his sons age be=y

x=2y

16yrs later,

(x-16)=6(y-16)

x-16=6y-96

x-16+96=6y

x+80=6y

2y+80=6y

80=4y

y=20yrs

x=10yrs

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