Math, asked by 9652, 9 months ago

ravi Manish and naveen alone can complete the work in 30days,15days and 10days respectively.they started the work together but ravi leaves the work after 2 days of the starting and Manish leaves the work after 3days more.in how many days naveen will complete the remaining work?​

Answers

Answered by mahithar
1

Answer:

55 days

Step-by-step explanation:

Answered by rahul123437
0

Naveen will complete the remaining work in one day.

Given:

Ravi Manish and naveen alone can complete the work in 30days,15days and 10days respectively.

They started the work together but ravi leaves the work after 2 days of the starting and Manish leaves the work after 3days more.

To find:

How many days naveen will complete the remaining work.

Explanation:

Ravi do work in one day = \frac{1}{30}

Manish do work in one day = \frac{1}{15}

Naveen do work in one day = \frac{1}{10}

So total Ravi Manish and naveen will do work in one day =  \frac{1}{30} + \frac{1}{15} +  \frac{1}{10}

They started the work together but ravi leaves the work after 2 days

That is all three are working 2 days.

So Total two days work =  \frac{2}{30} + \frac{2}{15} +  \frac{2}{10} = \frac{24}{60}  work complied in two days.

After that Ravi left work and three day work manish and naveen

So three day work of manish and naveen = \frac{3}{15} +  \frac{3}{10} = \frac{30}{60}

So total work done till now = \frac{24}{60} + \frac{30}{60} = \frac{54}{60}

Remaining work = 1- \frac{54}{60} = \frac{6}{60} = \frac{1}{10}

This work can complete naveen only

Its one day naveen work.

So naveen can complete work in 1 day.

To learn more....

1)1/24+1/28+1/36=?  this is a time and work problem.

https://brainly.in/question/6864885

2)How did you find absent days and working days in time and work aptitude problem.

https://brainly.in/question/8040678

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