Math, asked by rudra8520247, 10 months ago

ravi paurav and suraj together complete a work in 4 days. ravi can do it alone in 12 days abd paurav alone in 15days.how many days will Suraj take to complete the work if he works alone?​

Answers

Answered by Guruprasad56
1

Answer:

sorry bro....i am not good at it

Answered by sujitrico
4

Answer:

Suraj takes 10 days to complete the work if he works alone.

Step-by-step explanation:

Suppose, total work is X.

Ravi takes 12 days to do X. So he does (X/12) amount of work in 1 day.

Purav takes 15 days to do X. So he does (X/15) amount of work in 1 day.

Let, Suraj takes M days to do X. So he does (X/M) amount of work in 1 day.

They together do [(X/12) + (X/15) + (X/M)] amount of work in 1 day.

So they together do 4*[(X/12) + (X/15) + (X/M)] amount of work in 4 days.

Now, according to the question they together completed the X amount of work in 4 days.

So,

4*[(X/12) + (X/15) + (X/M)] = X

or, M= 10

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