Question

Ravi's father is 4 times as old as Ravi . After 20 years , he will be twice the age of his son. Find their present ages

Answer 1

Answer:

Step-by-step explanation:

Let Ravi's present age be x.

Ravi's father's present age=4x.

After 20 years,

Ravi's age=x+20

Ravi's father's age=4x+20

According to the condition,

4x+20=2(x+20)

4x+20=2x+40

2x=20

x=20/2=10

Thus, Ravi's present age=x= 10 years

Ravi's father's present age=4x= 4×10=40years

Answer 2

Answer:

Step-by-step explanation:

Let Ravi's present age = x years

According to condition

Ravi's father's present age = 4x years

After 20 years

Ravi's age =x+20 years

Father's age=4x+20 years

According to condition

2(x+20) =4x+20

2x+40=4x+20

40-20=4x-2x

20=2x

x=20÷2

x=10

Therefore Ravi's present age is equal to 10 years

His father's age =4x

= 4 ×10 years

= 40 years

Hope you have now got it !!!!