Question

ravi travel 3 km in the east and turn to south and moves 4 km how far is he from the starting point​

Answer 1

Answer:

The answer of the problem is 5km

Explanation:

                                                        North

           West                     (A) Starting point------3 km--- (B)                     East

                                                                                         ║

                                                                                       4km

                                                                                         ║    

                                                                                       (C)

                                                       South

By using the Pythagorean theorem:

    Hypotenuse = √perpendicular²+base²

      AC= √BC²+AB²

            = √4²+3²

            = √16+9

            =√25

            = 5

          ∴ AC= 5

Therefore, Ravi is 5km away from the starting point.

Answer 2

Answer:

Ravi is $5$ km far from the starting point.

Explanation:

We have been given that, Ravi travels $3$ km in the east and turns to the south, and moves $4$ km.

We have to find his distance from the starting point.

We will go further by using Pythagoras' theorem.

Here, $4$ km is the perpendicular and $3$ km is the base, we have to find out the value of the hypotenuse.

According to the Pythagorean theorem,

$Hypotenuse = \sqrt{Perpendicular^{2} +Base^{2}$

Substituting the values in the above equation we get,

$Hypotenuse = \sqrt{4^{2} +3^{2}$

$= \sqrt{16+9}$

$= \sqrt{25}$

$= 5$

Therefore, Ravi is $5$ km far from the starting point.