Question

Ravi was asked to find the LCM of two numbers. But he calculated their HCF and the value obtained is equal to one-third of the value he was supposed to find. If one of the numbers is twice the HCF, then the other number is equal to​

Answer 1

Step-by-step explanation:

Question:

Ravi was asked to find the LCM of two numbers. But he calculated their HCF and the value obtained is equal to one-third of the value he was supposed to find. If one of the numbers is twice the HCF, then the other number is equal to

Solution:

Let,

the LCM = x

then, the HCF = x/3

one of the numbers = 2 × x/3 = 2x/3

let the other number = ax

LCM × HCF = 1st number × 2nd number

x × x/3 = 2x/3 × ax

x²/3 = 2ax²/3

x² = 2ax²

a = 1/2

Answer 2

let the number be x and y

HCF of x and y =1/3 of the LCM

3 × x × y = LCM

if x is twice the HCF then y should be equal to the LCM of x and y