Question

Ravi works as a cashier in a bank. He has currency of
denominations 100, 50, 10 respectively. The ratio
of number of these notes is 2:3:5. The total cash with
Ravi is 4,00,000.
How many notes of cash of each denomination does he
have?​

Answer 1

Answer:

Let the number of Rs.100 notes =2x

Number of Rs.50 notes =3x

And Number of Rs.10 notes =5x

∴ Total Money =(2x×100)+(3x×50)+(5x×10)

200x+150x+50x=400x

But according to the problem the total money is Rs.4,00,000

⇒ 400x=4,00,000

x=  

400

400000

​  

=1000

Therefore number of Rs.100 notes 2x=2×1000=2000

Number of Rs.50 notes =3x=3×1000=3000

Number of Rs.10 notes =5x=5×1000=5000

Step-by-step explanation:

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Answer 2

Answer:

5000

Step-by-step explanation:

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