ravinder leaves home everyday at 8 am and reaches office at 9.30am.one day he left his home at 8 am but travelled a third of the distance at 3/4th of usual speed. at how many times his normal speed did ravinder travel the remaining part of the journey if he managed to reach office at time
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Let Govinda take x mins to reach office
Let his usual speed be v
As distance to his office is same in both cases and as distance=speed×time
⇒ vx=(
5
4
v)(x+22.5)
⇒ 5x=4x+90
x=90 minutes
I know I am not right but I have this answer only as it was in my text book
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