Question

Ravinder Singh borrowed a sum of ₹ 1800 for a certain period at the rate of 10% per
annum and returned ₹27750 on expiry of the time. Find the time for which money was
borrowed by him?​

Answer 1

Given :

Principle : ₹1800

Rate of interest : 10%

Total Amount : ₹27750

To find :

The time for which money was borrowed by him.

Solution :

First, we should find the simple interest.

Simple Interest :

$\sf \dashrightarrow Total \: Amount - Principle$

$\sf \dashrightarrow 27750 - 1800$

$\sf \dashrightarrow Rs.25950$

Now, we can find the time took to return the money.

$\sf \dashrightarrow SI = \dfrac{P \times R \times T}{100}$

$\sf \dashrightarrow 25950 = \dfrac{1800 \times 10 \times T}{100}$

$\sf \dashrightarrow 25950 = \dfrac{18000 \times T}{100}$

$\sf \dashrightarrow 519 = \dfrac{18000 times T}{2}$

$\sf \dashrightarrow 519 = \dfrac{9000 \times T}{1}$

$\sf \dashrightarrow T = \dfrac{519}{9000}$

$\sf \dashrightarrow T = 0.057$

Hence, the time taken to return the money back is 0.057 years.