Question

Ravish wanted to make a temporary shelter for his car by making a box like structure with tarpaulin that covers all the four sides on the top of the car.assuming that the stitching margins are very small and therefore negligible how much tarpaulin would be required to make the shelter of height 2.5 metre with base dimensions 4m×3m?

Answer 1

As the height, length and width of the shelter is given then the answer is CSA of the box *area of the top.
2(l+b)+lb.

Answer 2

Step-by-step explanation:

$\huge \underline \mathbb {SOLUTION:-}$

Let l, b and h be the length, breadth and height of the shelter.

Given:

l = 4m

b = 3m

h = 2.5m

Tarpaulin will be required for the top and four wall sides of the shelter.

Using formula, Area of tarpaulin required = 2(lh + bh)+lb

Put the values of l, b and h, we get

= [2(4 × 2.5 + 3 × 2.5) + 4 × 3] m²

= [2(10 + 7.5) + 12]m²

= 47 m²

Therefore, 47 m² tarpaulin will be required