raw the graph of 2x + 3y = 12 and 2y –1 = x on a graph paper, shaded the region between lines and x-axis. Also, find the area of shaded region
Answers
EXPLANATION.
Graph of the equation.
⇒ 2x + 3y = 12. - - - - - (1).
⇒ 2y - 1 = x. - - - - - (2).
As we know that,
From equation (1), we get.
⇒ 2x + 3y = 12. - - - - - (1).
Put the value of x = 0 in the equation, we get.
⇒ 2(0) + 3y = 12.
⇒ 3y = 12.
⇒ y = 4.
Their Co-ordinates = (0,4).
Put the value of y = 0 in the equation, we get.
⇒ 2x + 3(0) = 12.
⇒ 2x = 12.
⇒ x = 6.
Their Co-ordinates = (6,0).
From equation (2), we get.
⇒ 2y - 1 = x. - - - - - (2).
Put the value of x = 0 in the equation, we get.
⇒ 2y - 1 = (0).
⇒ 2y - 1 = 0.
⇒ 2y = 1.
⇒ y = 1/2.
⇒ y = 0.5.
Their Co-ordinates = (0,0.5).
Put the value of y = 0 in the equation, we get.
⇒ 2(0) - 1 = x.
⇒ - 1 = x.
⇒ x = - 1.
Their Co-ordinates = (-1,0).
Both curves intersects at a point = (3,2).
As we know that,
Area of triangle = 1/2 x Base x Height.
⇒ Base = 6 - (-1) = 7 cm.
⇒ Height = 2 cm.
Area of triangle = 1/2 x 7 x 2.
Area of triangle = 7 sq. units.
Answer:
Given:-
- Graph of the equations
- 2x+3y= 12
- 2y-1=x
To find :-
- Plotting the graph and
- Finding area of triangle.
Explanation :-
Here given two graph solutions
- 1)2x+3y=12 (i)
- 2)2x-1=x (ii)
- FROM THE EQUATION 1 WE GET
- 2x+3y=12
- Here putting the value of x = 0 in equation
- 2 (0)+3y=12
- 0 +3y=12
- y =12/3
- y = 4.
Their coordinates is =(0,4)
Now putting the value of y=0 in equation we get that,
- 2x+3 (0)=12
- 2x + 0 =12
- 2x =12
- x =12/2
- x =6.
Their coordinates is =(0,6).
- From equation 2 we get,
Putting x =0 in equation 2 we get,
- 2y-1=x
- 2y-1=(0)
- 2y =1
- y=1/2
Their coordinates is=(0,0.5)
- Putting the value of y=0 in equation ii) we get
- 2y-1=x
- 2(0)-1=x
- 0-1=x
- -1=x
Their coordinates is =(1,0).
Both these curves are intersect at a point of =(3,2)
- At the last we should find area of triangle
- Area of triangle =1/2×base×height
- Here ,
- Base=6-(-1)=7
- Height=2cm
- Area of triangle =1/2×7×2
- Area of triangle =7sq.units.