raw the graph of 2x + 3y = 12 and 2y –1 = x on a graph paper, shaded the region between lines and x-axis. Also, find the area of shaded region. who give correct answer will marked as brainlist
Answers
Step-by-step explanation:
Given:
To find: Draw the graph of 2x + 3y = 12 and 2y –1 = x on a graph paper, shaded the region between lines and x-axis. Also, find the area of shaded region.
Solution:
Step 1: Find two points of eq1
Put x=0
A(0,4)
Put y=0
B(6,0)
Mark these points on graph.
Step 2: Find 2 points of second line.
Put x=0
C(0,0.5)
Put y=0
D(-1,0)
Mark these points on same graph and draw both lines.
Step 3: Shaded the region between lines and x-axis.It is ∆DEB.
Step 4: Find the area of Shaded region.
Area of ∆DEB=1/2×BASE×HEIGHT
Base=DB= 7 units
Height = FE= 2units
Area of ∆DEB=1/2×7×2
=7 sq-units
Area of ∆DEB = 7 sq-units
Final answer:
Area of ∆DEB = 7 sq-units
Intersection of lines are (3,2)
Hope it helps you.
To learn more on brainly:
1)solve the following system of linear equation graphically: 3x+y-11=0 and x-y-1=0
shade the region bounded by these lines...
https://brainly.in/question/3050092
2) Solve the following pair of linear equations graphically. Also write the observations.
(i) x + y = 1 ; 2x - 3y = 7
https://brainly.in/question/41675964