Question

raw the graph of 2x + 3y = 12 and 2y –1 = x on a graph paper, shaded the region between lines and x-axis. Also, find the area of shaded region. who give correct answer will marked as brainlist

Answer 1

Step-by-step explanation:

Given:

$2x + 3y = 12 \:...eq1\\ 2y - 1 = x\:...eq2$

To find: Draw the graph of 2x + 3y = 12 and 2y –1 = x on a graph paper, shaded the region between lines and x-axis. Also, find the area of shaded region.

Solution:

Step 1: Find two points of eq1

Put x=0

$2(0) + 3y = 12 \\ \\ y = \frac{12}{3} \\ \\ y = 4$

A(0,4)

Put y=0

$2x + 3(0) = 12 \\ \\ 2x = 12 \\ \\ x = 6$

B(6,0)

Mark these points on graph.

Step 2: Find 2 points of second line.

Put x=0

$2y - x = 1 \\ 2y - 0 = 1 \\ \\ y = \frac{1}{2} \\ \\ y = 0.5$

C(0,0.5)

Put y=0

$2(0) - x = 1 \\ \\ - x = 1 \\ \\ x = - 1$

D(-1,0)

Mark these points on same graph and draw both lines.

Step 3: Shaded the region between lines and x-axis.It is ∆DEB.

Step 4: Find the area of Shaded region.

Area of ∆DEB=1/2×BASE×HEIGHT

Base=DB= 7 units

Height = FE= 2units

Area of ∆DEB=1/2×7×2

=7 sq-units

Area of ∆DEB = 7 sq-units

Final answer:

Area of ∆DEB = 7 sq-units

Intersection of lines are (3,2)

Hope it helps you.

To learn more on brainly:

1)solve the following system of linear equation graphically: 3x+y-11=0 and x-y-1=0

shade the region bounded by these lines...

https://brainly.in/question/3050092

2) Solve the following pair of linear equations graphically. Also write the observations.

(i) x + y = 1 ; 2x - 3y = 7

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