Question

Ray
(3) With the help of fig 3.64 (iii),
Fill in the blanks and write proof.
is the opposite ray of ray BC.
Now, ZABE = = m( ) ...... proved in (ii).
.. 180 -
AFB) ..... linear pair
= [360 - m
... 180 - ZABC = 180 - m(arc ADB)
..- ZABC - - 5 m
.. ZABC = = m(arc ADB)
.M
E B C
Fig. 3.64(ii)

(from std X geometry book ..SSC)​

Answer 1

ANSWER (•‿•)

HOPE THIS ANSWER HELPS YOU!!

Answer 2

Solution:

• We can clearly see the ray passing and it is mentioned $AB$ in the figure, therefore the first blank would be Ray $AB$.
• For the second blank we already know that Δ$ABE=ABC$
• The angle would be $180^{0}$, therefore we can write as,

         $180^{0} -180^{0}=\frac{1}{2} m(arcAFB)$

• We can write as Δ$AFB=ABD$, therefore

        $=\frac{1}{2}[360 - m(ABD)]$

• Therefore we can write all the other blanks easily as,

       Δ$ABC=-\frac{1}{2} m(arcADB)$

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