Ray of incident at an angle theta and reflecting place has face of emergence
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Solution
A=5°
p=15
13
=0°
T2
=0°
1
+ry =A
1
=A—1ro
=5-0=5°
sin 41
p=
sin ry
sini; = psinrg
= 1.5 x sin5°
=1.5x 0.087
= 0.1305
=17.5°
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