Ray OS stands on a line POQ. Ray OR and ray OT are angle Bisectors of POS and SOQ, respectively. If POS=x, find ROT.
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Solution:
Ray OS stands on the line POQ.
therefore,
∠POS + ∠SOQ = 180°
But,
∠POS = x
Therefore,
x + ∠SOQ = 180°
So,
∠SOQ = 180° - x
Now, ray OR bisects ∠POS, therefore,
∠ROS = 1/2 × ∠POS
= 1/2 × x = x/2
∠SOT = 1/2 × ∠SOQ
= 1/2 × (180°-x)
= 90° - x/2
Now,
∠ROT = ∠ROS + ∠SOT
= x/2 + 90° - x/2
= 90°
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Anonymous:
mast.!
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