ray OS stands on a line POQ . Ray OR and ray OT are angle bisectors of angle POS and angle SOQ , respectively. If angle POS = x , find angle ROT.
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poq is a straight line and ray os stands on it.
thus, angle pos + angle soq = 180
angle pos = x
thus, angle soq = 180 - x
now,
angle ros = 1/2 angle x. (RO is angle bisector)
and
angle sot = 1/2 (180 - x) (OT is angel bisector)
now,
angle rot = angle ros + angle sot
ROT = 1/2*x + 1/2(180 - x)
ROT = 1/2x + 90 - 1/2x
ROT = 90
thus, angle pos + angle soq = 180
angle pos = x
thus, angle soq = 180 - x
now,
angle ros = 1/2 angle x. (RO is angle bisector)
and
angle sot = 1/2 (180 - x) (OT is angel bisector)
now,
angle rot = angle ros + angle sot
ROT = 1/2*x + 1/2(180 - x)
ROT = 1/2x + 90 - 1/2x
ROT = 90
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