Question

Raymond Traveller 2 by 5 of his journey by train 1 by 3 taxi 1 by 6 bus and remaining 10 km foot
find the length of the total general

Answer 1

let the total distance be x

then 2by5 of his journey = 2x/5

1by6 of his journey=1x/6 

1by3 of his journey = x/3

then 

2x/5 + x/6 + 10 + x/3=x

(12x+5x+30+10x)/30  =x

10x+17x+30=30x

30=30x-17x-10

30=3x

x=30/3

x=10km

then

2/5 of 10 =4km

1/3 of 10 =10/3 km

1/6 of 10 =5/3 km

10 =10km

then 

4+10+5/3+10/3=x

14+15/3 =x

(42+15)/3 =x

57/3 =x

19 km = x

the total distance travelled by raymond is 19km 

i hope this much will nhelp you