Question

Rays from a point source of light situated below the water surface form a circular patch of light of radius 30cm on the surface. At what depth is the light source situated? μ (Refractive index) = 1.33​

Answer 1

Answer:

3m

Explanation:

When the ray of light is incident from water-air interface at critical angle (θc)(θc), the refracted ray becomes parallel to the interface.

Hence, the radius of the circular bright patch of light noticed on the surface of water is given by

R=htanθcR=htanθc (see figure)

=7–√sinθccosθc=7–√=7sin⁡θccos⁡θc=7

1/μ1−1μ2√1/μ1−1μ2

=7√μ2−1√=7μ2−1

=3m

hope this will help u

Mark me as brainliest