Physics, asked by aymansyed70, 9 months ago

Rays from Sun converge at a point 15 cm in front of a concave mirror. Where should an object be placed so that size of its image is equal to size of the object?
(a) 15 cm in front of the mirror.
(b) 30 cm in front of the mirror.
(c ) between 15 cm and 30 cm in front of the mirror.
(d) more than 360 cm in front of the mirror.
pls fast

Answers

Answered by ss70506686
7

Answer:

(b) 30cm in front of the mirror.

Explanation:

it is stated that the ray converge 15cm in front that means the focus of the lens is 15cm in front so the center of curvature will be 30 cm in front.

Hope it helps and you will mark it as Brainliest

Answered by vihitparekh21
1

Answer:

(b) 30 cm in front of the mirror.

Explanation:

It is given that the rays of sun converge at a point 15 cm in front of the concave mirror.

We know that light rays coming from infinity passes through the focus of the concave mirror.

Also twice of focal length is the center of curvature of the concave mirror.

When the object is kept at the center of curvature of concave mirror we get image of the same size as that of object.

So the object should be kept at 30 cm in front of the concave mirror to get image of the same size as that of object.

So the correct answer is ( b )

Hope it helps. :)

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