Physics, asked by shebamshyju, 1 day ago

Rays from Sun converge at a point 15 cm in front of a concave mirror. Where should an
object be placed so that size of its image is equal to the size of the object?

A. 30 cm in front of the mirror

B. 15 cm in front of the mirror

C. Between 15 cm and 30 cm in front of the mirror

D. More than 30 cm in front of the mirror
Thanks Harsh bro ​

Answers

Answered by sardevi2005
4

Answer:

Option B. is correct

15cm in front of mirror.

Explanation:

Hope it helps you :)

Answered by xxcuteboyxx62
4

\begin{gathered}\huge\blue{\mid{\fbox{\tt{SOLUTION}}\mid}} \\ \end{gathered}

- ( B')30 cm in front of the mirror

  1. The ray diagram illustrates that, in case of a concave mirror, the image size becomes equal to the object size when the object distance equals the radius of curvature, i.e, twice the focal length. . .

So, the object has to be placed at a distance of ( 15 × 2 ) = 30 cm in front of the concave mirror. . .

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