Rays from sun converge at a point 15cm in front of a mirror where should an object be placed so that size of its image is equal to the size of the object?
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It is given that sun rays converge at 15 cm. So, focal length of the mirror = f = 15 cm.
In case of a concave mirror, the size of image and object will be same if the object is placed at 2f.
Hence, in this case object must be place at 2f or 2 × 15 = 30 cm.
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