Question

Rays from sun converge at a point cm in front of a concave mirror. Where should an

object be placed so that size of its image is equal to the size of the object.

Don't copy​

Answer 1

In the problem, it is given that the sun rays converge at 15 cm. So, the focal length of the mirror =f = 15 cm. In the case of a concave mirror, the size of the image and object will be the same if the object is placed at 2f. ∴ In this case, the object must be placed at 2f.

Answer 2

Answer:

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