rays from the sun converge at a point 15 cm in front of a concave mirror where should an object be placed so that the size of its img is equal to the size of the object?
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Answer:In the problem, it is given that the sun rays converge at 15 cm. So, the focal length of the mirror =f = 15 cm. In the case of a concave mirror, the size of the image and object will be the same if the object is placed at 2f. ∴ In this case, the object must be placed at 2f.
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I don't know, just receiving my points to get till Genius
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