Question

Rays of light are entering from glass to glycerin. If the absolute refractive index of glass is 1.5 and that of glycerin is 1.47 then find the refractive index of glycerin with respect to glass.

Answer 1

Given :

➾ Ref. index of glass n¹ = 1.5

➾ Ref. index of glycerin n² = 1.47

To Find :

➨ Refractive index of glycerin wrt glass.

Concept :

➠ Refractive index of a medium is defined as the factor by which speed of light reduces as compared to the speed of light in vacuum.

➠ More (less) refractive index implies less (more) speed of light in that medium, which therefore is called denser (rarer) medium.

➠ Refractive index of medium 2 wrt medium 1 is given by

✭ n²¹ = n²/ n¹

Calculation :

⇒ n²¹ = n² / n¹

⇒ n²¹ = 1.47/1.5

⇒ n²¹ = 0.98

Answer 2

Given:

• Absolute refractive index of glass is 1.5.
• Refractive index of Glycerine:- 1.47.

To Find:

Refractive index of glycerin with respect to glass.

Solution:

Let,

Consider glass as medium 1 and glycerin as medium 2.

Absolute refractive index of glass, $\sf\ n^1 = 1.5$

Absolute refractive index of glycerin, $\sf\ n^2 = 1.47$

Refractive index of glycerin with respect to glass $\sf\ = n^{21}$

Calculation:

$\dashrightarrow\: \sf\ =n^2/n^1$

$\dashrightarrow\: \sf\ = 1.47/1.5$

$\dashrightarrow\: \underline{\boxed{\bf{\purple{0.98}}}}$

•°• Refractive index of glycerin with respect to glass is 0.98.

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$\large\underline\bold{Additional\: Information}$

• A ray of light is a straight line path along which light travels.
• The index of refraction is defined as the speed of light in vacuum divided by the speed of light in the medium.
• Refractive Index of medium 2 with respect to medium 1 = n2 / n1.

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