Question

Raza is twice as old as rabia and Kamran is 7 years younger than raza. If the sum of their ages is 38 years find their respective ages

Answer 1

Answer:

Let the Age of Rabia be n yrs.

★ According to First Statement :

↠ Raza = Twice of Rabia

↠ Raza = 2 × n

↠ Raza = 2n — eq. ( I )

★ According to Second Statement :

↠ Kamran = 7 years younger than Raza

↠ Kamran = Raza – 7

• putting value of Raza from eq. ( I )

↠ Kamran = (2n – 7) — eq. ( II )

_____________________

☯ Sum of Ages :

⇴ Rabia + Raza + Kamran = 38

• putting value from eq. ( I ) & eq. ( II )

⇴ n + 2n + 2n – 7 = 38

⇴ 5n = 38 + 7

⇴ 5n = 45

• Dividing both term by 5

⇴ n = 9

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☯ RESPECTIVE AGES :

⟶ Rabia = n = 9 years

⟶ Raza = 2n = 2(9) = 18 years

⟶ Kamran = (2n – 7) = 2(9) – 7 = 11 years

∴ Age of Rabia, Raza & Kamran is 9 years, 18 years & 11 years respectively.

Answer 2

AnswEr:-

Present ages of Raza,Rabia & Kamran are 18 years,9 years & 11 years respectively.

$\rule{200}{1}$

Let present age of Raza,Rabia & Kamran be a, b & c years respectively.

According to question:-

↠ a = 2b -----(eq.1)

↠ c = a - 7 ------(eq.2)

↠ a + b + c = 38 -----(eq.3)

Now putting value of (eq.1) & (eq.2) in (eq.3):-

↠ 2b + b + a - 7 = 38

↠ 3b + 2b - 7 = 38

↠ 5b - 7 = 38

↠ 5b = 38 + 7

↠ 5b = 45

↠ b = 45/5

↠ b = 9 years.

Therefore,present age of Rabia = 9 years

Now putting this value in (eq.1) :-

↠ a = 2 × 9

↠ a = 18 years.

Therefore,present age of Raza = 18 years

Now putting this value in (eq.2):-

↠ c = 18 - 7

↠ c = 11 years.

Therefore,present age of Kamran = 11 years.

So to say,

Present ages of Raza,Rabia & Kamran are 18 years,9 years & 11 years.