Question

RD Sharma class 9 solution RD Sharma class 9 solution​

Answer 1

1 ) AB = CD [ opposites sides of a parallelogram are always equal]

AB = EF [ opposites sides of a rectangle are always equal]

CD = EF

Adding AB both sides,

AB + CD = AB + EF ……….(i)

Off all the segments that can be drawn to a given line from a point not lying on it, the perpendicular segment is the shortest.

BE < BC and AF < AD

BC > BE and AD > AF

BC + AD > BE + AF ……….(ii)

From eq. (i) and (ii),

AB + CD + BC + AD = AB + EF + BE + AF

2) BD = DE = EC = BC

Draw AFBC

ar (ABC) = ……….(i)

and ar (ABD) = ……….(ii)

= =

= ar (ABC) ……….(iii)

And ar (AEC) = ar (ABC) ……….(iv)

From (ii), (iii) and (iv),

ar (ABD) = ar (ADE) = ar (AEC)