Question

rdr/(r²+x²)³/² integrate this



sorry I couldn't write properly
3/2is the power of whole(r²+x²)​

Answer 1

Step-by-step explanation:

Assume,

${r}^{2} + {x}^{2} = {t}^{2}$

Differentiating w.r.t r we get,

$rdr = tdt$

So the integral can be written as

$\frac{tdt}{ {t}^{3} } = \frac{dt}{ {t}^{2} }$

And integral of this would be,

$\frac{ - 1}{t}$

Resubstituting we get,

$\frac{ - 1}{ \sqrt{( {x}^{2} + {r}^{2} ) } }$