Question

re
4.
Find the angle between t
straight lines 3x2 – 5xy-1
tid
y + 10 = 0​

Answer 1

Answer:

6x

2

−xy−5y

2

=0

Substitute t=

y

x

6t

2

−t−5=0

⇒t=

12

1±

1+120

⇒t=

12

1±11

⇒t=1,

6

−5

y=x or y=

5

−6

x

∴3x

2

−5xy+py

2

=0

t=

y

x

, 3t

2

−5t+p=0

If, t=1,p=2

And If, t=

6

−5

,p=5×(

6

−5

)−3×

36

25

=

36

−25×6

−

36

75

=

36

−225

p=

4

−25

So, p=2 or

4

−25

are two values.

Step-by-step explanation:

plz mark me as brain list and follow me