Math, asked by eldho, 1 year ago

re group the following terms and factorise 12ab-8b-6+9a

Answers

Answered by divya00000
11
12ab-8ab-6+9a
=12ab+9a-8b-6
=3a(4b+3)-2(4b+3)
=(3a-2)(4b+3)

Anonymous: Nic
Answered by fadilsrjalal
3

Answer:


Step-by-step explanation:

12ab-8ab-6+9a

=12ab+9a-8b-6

=3a(4b+3)-2(4b+3)

=(3a-2)(4b+3)

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