re group the following terms and factorise 12ab-8b-6+9a
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12ab-8ab-6+9a
=12ab+9a-8b-6
=3a(4b+3)-2(4b+3)
=(3a-2)(4b+3)
=12ab+9a-8b-6
=3a(4b+3)-2(4b+3)
=(3a-2)(4b+3)
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Answered by
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Answer:
Step-by-step explanation:
12ab-8ab-6+9a
=12ab+9a-8b-6
=3a(4b+3)-2(4b+3)
=(3a-2)(4b+3)
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