Question

re group the following terms and factorise 12ab-8b-6+9a

Answer 1

Given:

Given expression is, $12ab - 8b - 6+9a$.

To find:

We need to regroup the given terms and factorize the given expression.

Solution:

Consider the given expression,

$\Rightarrow 12ab - 8b - 6+9a$

Rearranging the terms,

$\Rightarrow 12ab +9a- 8b - 6$

Now, we should factorize the above expression.

Taking $3a$ common from first two terms, we get

$\Rightarrow 3a(4b +3)- 8b - 6$

Taking $-2$ common from last two terms, we get

$\Rightarrow 3a(4b +3)- 2(4b+3)$

Taking $4b+3$ common from the above expression, we get

$\Rightarrow (4b +3)(3a-2)$

The above expression cannot be simplified further because there are no common terms in the above expression.

Therefore, the required factored form of given expression is equal to

$(4b +3)(3a-2)$.