Question

Reaction :

2Br¯ + H2O2 + 2H+  Br2 + 2H2O

take place in two steps :

(a) Br¯ + H+ + H2O2 slow HOBr + H2O

(b) HOBr + Br¯ + H+ fast

 H2O + Br2

The order of the reaction is –

(A) 3 (B) 6 (C) 5 (D) 0​

Answer 1

Answer:

Reaction :

2Br¯ + H2O2 + 2H+  Br2 + 2H2O

take place in two steps :

(a) Br¯ + H+ + H2O2 slow HOBr + H2O

(b) HOBr + Br¯ + H+ fast

 H2O + Br2

The order of the reaction is –

(A) 3 (B) 6 (C) 5 (D) 0

Answer 2

Answer:

3

Explanation:

2Br- +H2O2 +2H+ ———>Br2 +2H20

Rate =k(H2O2)(H+)(Br-)

The rate constant is directly proportional to the concentration of bromide ions [Br] ions. As the concentration of bromide ion increases the rate constant value increases.