reaction aA+bB ---> product the rate of reaction= k[A]^3 [B]^0 if concentration of A is doubled and concentration of B is half the rate will be?
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Answer:
−{d[A]/dt}=−{4d[B]/dt}
Explanation:
−{d[A]/dt}=−{4d[B]/dt}
aA+bB⇒ Product
Rate = K[A]
a
[B]
b
On doubling A
Rate →4 times
⇒a=2
On making concentration of B four times
Rate →2 times
b=1/2
∵ROR=
a
−1
dt
d[A]
=−
b
1
dt
d[B]
dt
−d[A]
=−4
dt
d[B]
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