Question

reaction between acetyl chloride and dimethyl cadmium

Answer 1

2CH3COCl  +  Cd(CH3)2  ------------------->    2CH3COCH3  + CdCl2

Answer 2

The reaction of acetyl chloride and dimethyl cadmium is an alkylation reaction.  

We know that, the formula of acetyl chloride is $CH_3COCl$ and chemical formula for dimethyl cadmium is $(CH_3)_2CdCl$.

The reaction is given below:

$\mathrm{CH}_{3}-\mathrm{CO}-\mathrm{Cl}+\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CdCl} \rightarrow \mathrm{CH}_{3} \mathrm{COCH}_{2} \mathrm{CH}_{3}+\mathrm{CdCl}_{2}$

Here dimethyl cadmium acts as alkylating reagent that provide methyl group which can replace the $Cl^-$ group from acetyl chloride. Hence, acetyl chloride acts as alkylating reagent.

The final product formed is called as 2-butanone as it is a ketone with >C=O (carbonyl group) at 2nd position.