Question

reaction between N2 and O2 takes place as follows :
2N2(g)+O2(g)---------->2N2O


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Answer 1

Answer:

6.58 × 10^-21 M

Explanation:

k is very small, which means negligible amounts of N2 and O2 react .

it means conc. of reactants at intial ≈ conc . at equilibrium .

so,

conc. of N2 = [ N2 ] = (0.482 - 2x)/10 = 0.482/10

= 0.0482

conc. of O2 = [O2 ] = (0.933 - x)/10 = 0.933/10

= 0.0933

Kc = [N2O]²/[N2]² [O2]

2 × 10^-37 = [2x/10]²/(0.0482)² (0.0933)

2 × 10^-37 = 4x²/100(0.0482)² (0.0933)

x² = 10.837 × 10^-40

take square root

x = 3.292 × 10^-20

hence, conc. of [N2O] = 2x/10 = 2 × 3.92 × 10^-20/10 = 6.58 × 10^-21 M.