Chemistry, asked by kirangarg198, 3 months ago

reaction for n heptane aromatozation reaction​

Answers

Answered by lailaalif2002
1

Answer:

The reaction of n-hexane and 1-hexene has been investigated on unsupported and supported Mo2C catalysts. Pure Mo2C catalyses the dehydrogenation and aromatization of n-hexane at and above 723K. Benzene was formed with the highest selectivity, 65%, at 773–823K at a conversion of 25%.

Answered by atharv0437
12

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Aromatization is a chemical reaction in which an aromatic system is formed from a single nonaromatic precursor. Typically aromatization is achieved by dehydrogenation of existing cyclic compounds, illustrated by the conversion of cyclohexane into benzene.

The deactivation of Pt/KL catalyst during n-heptane aromatization reaction was investigated. The activity fell quickly, especially in the initial stage. The fresh, the used and the regenerated catalysts were characterized by N2 physisorption, HADDF-STEM, TGA, UV-Raman, etc. The rapid deactivation is attributed to declined accessibility to Pt active sites because of coke deposition. GC-MS analysis revealed that the coke species are polycyclic aromatic hydrocarbons (PAHs). The dimensions of coke molecules and the coke volumes of used catalysts were estimated via DFT calculations. The variation of the contents of different coke species with reaction time implies a shape-selective transformation under micropore constraints. This, together with the XPS-determined depth profile of the coke in the used catalyst, indicates most of the coke was internally encased near the micropore openings. Quantitative evaluation concerning the influence of coke deposition on micropore volume confirms severe channel blockage by coke.

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