Reaction H2(g) + I2(g) → 2HI; AH = 12.40 Kcal.
According to this, heat of formation of HI will be -
(1) 12.40 Kcal
(3) - 6.20 Kcal
(2) – 12.40 Kcal
(4) 6.20 Kcal
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Heat of formation is for one mole of HI
So answer will be 6.2 Kcal
HOPE THIS HELPS!!
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