Question

Reaction is first order in A and second order in B.How is the rate affected when concentration of both A and B are doubled *



6 times

8 times

5 times

9 times

​

Answer 1

Answer:

8 times

Explanation:

It is given that a reaction is first order in A and second order in B.

i) The differential rate equation is as follows:

Rate =k[A][B]

2

(ii) On increasing the concentration of B three times, rate becomes 9 times.

(d[B])

2

=3

2

=9

(iii) When the concentrations of both A and B are doubled, rate becomes 8 times.

d[A](d[B])

2

=2×2

2

=8

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