Question

Reaction of cac2o4 with water

Answer 1

Our balanced equation is:

NaCl + AgNO₃ -----------> NaNO₃ + AgCl

So, 1 mole of NaCl needs 1 mole of AgNO₃ to react completely

So, n AgNO₃ = M x V = 0.2 * 0.1 = 0.02 mole

n NaCl = M x V = 0.1 * 0.1 = 0.01 mole

As, AgNO₃ is present more than required, NaCl is our limiting agent

a) No. of moles of AgCl obtained = 0.01

Mass of AgCL formed = 0.01 * 143.5 [ mol.wt of AgCl ]

= 1.435 g of AgCl

b) AgNO₃ is present more than required, NaCl is our limiting agent.

 

c) Here AgNO₃ is present more than required (0.02 mole), NaCl is our limiting agent as it is present 0.01 mole less than AgNO₃. Thus unreacted or excess reagent is AgNO₃.

In our reaction 0.01 mole of NaCl require 0.01 mole out of 0.02 mole of AgNO₃ to form 0.01 mole of AgCl.

So, unreacted no. of moles of AgNO₃ = 0.01

Mass of AgNO₃ unreacted = 0.01 * 170

= 1.7 g of AgNO₃

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