Reaction of copper reacting with sodium thiosulfate
Answers
Sodium thiosulfate [Na2S2O3•5H2O] dissolves in water to give thiosulfate ion (S2O32-), a useful reducing agent. Copper (II) sulfate [CuSO4•5H2O] dissolves to give cupric ion (Cu2+); in the context of a redox reaction with thiosulfate, the cupric ion acts as an oxidizing agent. The vivid color of Cu2+ makes it easy to see when it's been reduced by the thiosulfate; the blue cupric ion becomes the colorless cuprous ion.
We can see from the reduction potentials that thiosulfate should reduce Cu2+ to Cu+, possibly all the way to copper metal. Does this happen in real life? We might expect a two-reagent redox system to give simple, predictable results. Here we do two experiments with copper (II) sulfate and sodium thiosulfate to see if the results are what we expect. The first one involves an equimolar ratio of copper sulfate to sodium thiosulfate; the second uses an excess of sodium thiosulfate.
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