Reaction of diborane and ammonia in 1:2 molar ratio at higher temperature (t - 200°C) yields a
product X. Which of the following statement(s) is/are true for X?
(A) It is called inorganic graphite.
(B) In this compound every boron as well as nitrogen is effectively sp2 hybridized.
(C) This compound is isoelectronic as well as isostructural with benzene.
(D) It is a slippery white solid with a layer structure at room temperature.
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Answer:
A) It is called inorganic graphite.
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