Reaction of the solid solution of aqueous solution of 0.01 m NaCI. If 37 'C, 0 .02 mol. General Chat Chat Lounge General Chat Chat Lounge Say, yes.
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Let the radii be r1 and r2 and height be h
Then volume is given by
\frac{\pi \times h}{3} \times ( {(r1)}^{2} + r1r2 + {(r2)}^{2} ) \\ = \frac{\pi \times 30}{3} \times ( {14}^{2} + 14 \times 7 + {7}^{2} ) \\ 10\pi \times 343 = 10780 \: {cm}^{3} \\ = 10.78 \: litresLet the radii be r1 and r2 and height be h
Then volume is given by
\frac{\pi \times h}{3} \times ( {(r1)}^{2} + r1r2 + {(r2)}^{2} ) \\ = \frac{\pi \times 30}{3} \times ( {14}^{2} + 14 \times 7 + {7}^{2} ) \\ 10\pi \times 343 = 10780 \: {cm}^{3} \\ = 10.78 \: liters q
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