Question

reaction SO2+ O2 -> SO3 given that 1.28g of SO2 is reacting 2.56g of O2 determine limiting reagent

Answer 1

Answer:

the process by which green plants turn carbon dioxide and water into food using energy from sunlight

Answer 2

Given:

Mass of SO₂ given = 1.28g

Mass of O₂ given = 2.56g

To find:

Limiting reagent

Solution:

The required balanced chemical reaction is-

2SO₂   +   O₂ →   2SO₃

according to stoichiometry,

2 moles of SO₂ reacts with 1 mole of O₂ and gives 2 moles of SO₃.

Molecular mass of SO₂ = 32 + 2×16

                                       = 64gmol⁻¹

Molecular mass of O₂ = 2× 16

                                     = 32 gmol⁻¹

Molecular mass of SO₃ = 32 + 3×16

                                       = 80 gmol⁻¹

So,

2×64 g of SO₂ reacts with O₂ = 32 g

1.28 g of SO₂ reacts with O₂ =  $\frac{32}{2 \times 64} \times 1.28$g

                                                = 0.32g

therefore, 1.28g of SO₂ reacts with 0.32g of O₂ to form SO₃.

given mass of O₂ is 2.56g.

Hence, SO₂ is limiting reagent as O₂ present in excess.