READ PROBLEM CAREFULLY.200 Mev energy is released by fission
from 2grams of 92U^235 undergoes fission. Find
no. of fissions per second required
for producing a power of 1 mega watt.
Answers
Answered by
1
Answer:
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Explanation:
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Answered by
1
Answer:
P=n(
t
E
)
⇒1000=
t
n×200×10
6
×1.6×10
−19
\displaystyle \Rightarrow \frac { n }{ t } =3.125\times { 10 }^{ 13 }⇒
t
n
=3.125×10
13
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