Question

Read the following information carefully and answer the questions given below. There is a solid cuboid, two opposite faces of it are painted black, two opposite faces are painted red and remaining faces are painted green. After painting, this cuboid is divided into 72 cubes so that 64 cubes of smaller size and 8 cubes of bigger size could be obtained. Bigger cubes have no face black. How many cubes have two or more faces painted?​

Answer 1

Answer:

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The larger cube is cut into 64 smaller cubes. This implies that the edge of a smaller cube is one-fourth that of the larger cube. We know that the two adjacent faces are painted red and the two faces opposite to these faces are painted black. This implies that the top and the bottom faces are painted green. Thus, there are two edges where the faces painted red and black meet, and each edge has four cubes. Thus, there are totally 88 smaller cubes on each face. So, there are 32 smaller cubes which have at least one of their faces green. The remaining 64 - 32 = 32 smaller cubes have none of their faces green.

Answer 2

The Correct choice is 32 smaller cubes are painted

• The larger cube is turn over sixty four smaller cubes. this means that the sting of a smaller cube is fourth that of the larger cube.

• we all know that the adjacent faces area unit painted red and therefore the two faces opposite to those faces area unit painted black.

• This means that the highest and therefore the bottom faces area unit painted inexperienced.

• Thus, there area unit 2 edges wherever the faces painted red and black meet, and every edge has four cubes.

• Thus, there area unit wholly eighty eight smaller cubes on every face.

• So, there area unit thirty two smaller cubes that have a minimum of one among their faces inexperienced.

• The remaining sixty four - thirty two = thirty two smaller cubes have none of their faces inexperienced.

Hence,

Hence,The Correct choice is 32 smaller cubes are painted.

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