Question

Read the following statements and choose the correct option;
Assertion: [A] A concave mirror of focal length 18 cm forms a virtual image with magnification less than 1, of an object placed 9cm from the mirror.
Reason: [R] Concave mirror forms virtual magnified image of an object placed between F and P of the mirror.. Single choice.

Both, A and R, are true and R is the correct explanation of A
Both, A and R, are true but R is not the correct explanation of A
If A is true but R is false
If A is false but R is true

Answer 1

$\LARGE{ \underline{ \blue{ \sf{Required \: answer:}}}}$

Concave mirror is of focal length 18 cm and the object is placed 9 cm from the mirror. This means, it is placed between the F and P. The image formed will be virtual, erect and magnified due.

So, The magnification (Image height/Object height) should be greater than 1. But according to Assertion, magnification is less than 1. Hence is incorrect.

The reason is providing the same thing that concave mirror will form virtual and magnified image when placed between F and P. Hence, it is correct.

So, The Assertion is X and the Reason is ✓

Option D✓

━━━━━━━━━━━━━━━━━━━━

Let's see, where the image is formed according to the position of object in Concave mirror.

• At infinity - At focus
• Between Infinity and C - Between C and F
• At C - At C
• Between F and C - Beyond C
• At F - Infinity
• Between F and P - Behind the mirror.

Answer 2

Answer:

${\huge{\underline{\overline{\rm{\color{yellow}{\longrightarrow Answer\checkmark}}}}}}</p><p></p><p>$

$\huge{\fcolorbox{yellow} {black}{\color{yellow}{ANSWER}}}$

Concave mirror is of focal length (f) 18 cm and the object is placed 9 cm in front of the mirror . This means it is placed between focus and P. The image formed will be erect, virtual and magnified.